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I have a dictionary like so:
my_dictionary = {
'key1': {'a': 1, 'b': 1, 'c': 10},
'key2': {'a': 1, 'b': 1, 'c': 11},
'key3': {'a': 1, 'b': 1, 'c': 12}
}
How can I compare the 'c' subkeys of this dictionary, find the greatest one, and return the corresponding parent key of that dictionary (in this case I want to output 'key3' as it's 'c' key is highest). Thanks!
解决方案
max optionally accepts a callable argument for modifying the comparison:
>>> d
{'key1': {'a': 1, 'b': 1, 'c': 10},
'key2': {'a': 1, 'b': 1, 'c': 11},
'key3': {'a': 1, 'b': 1, 'c': 12}}
>>> max(d, key=lambda v: d[v]['c'])
'key3'
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