Given an unsorted array, find the maximum difference between the successive elements in its sorted form.
Try to solve it in linear time/space.
Return 0 if the array contains less than 2 elements.
You may assume all elements in the array are non-negative integers and fit in the 32-bit signed integer range.
class Solution {
public:
int maximumGap(vector<int> &num) {
int sizes=num.size();
if(sizes<2)
return 0;
sort(num.begin(),num.end());
int pre=num[0];
int max=-1;
for(int i=1;i<sizes;i++)
{
if(num[i]-pre>max)
max=num[i]-pre;
pre=num[i];
}
return max;
}
};
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