*寒假水18——An easy problem(字母转换成数字）

we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).

InputOn the first line, contains a number T.then T lines follow, each line is a case.each case contains a letter and a number.Outputfor each case, you should the result of y+f(x) on a line.Sample Input

6
R 1
P 2
G 3
r 1
p 2
g 3

Sample Output

#include<iostream>
using namespace std;
int main()
{
 int a,i,n,j;
 char b;
 cin>>n;
 for(i=1;i<=n;i++)
 { cin>>b>>a;
  if('a'<=b&&b<='z')
   j=-(b-'a'+1);
  if('A'<=b&&b<='Z')
   j=b-'A'+1;
  cout<<a+j<<endl;
 }
}

题解：讲字母转换成数字：y=x-'a'+1。