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Problem Description
There must be many A + B problems in our HDOJ , now a new one is coming.
Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too.
Easy ? AC it !
Input
The input contains several test cases, please process to the end of the file.
Each case consists of two hexadecimal integers A and B in a line seperated by a blank.
The length of A and B is less than 15.
Output
For each test case,print the sum of A and B in hexadecimal in one line.
#include <iostream>
#include <string>
#include <stdio.h>
using namespace std;
int main()
{
__int64 a,b; //两个十六进制数小于15位，即转换成二进制数小于60位
while(scanf("%I64x%I64x",&a,&b)!=EOF){
if(a+b<0)
printf("-%I64X\n",-a-b);
else
printf("%I64X\n",a+b);
}
return 0;
}
-a-b);
else
printf("%I64X\n",a+b);
}
return 0;
}
【后记】
1.感觉到现在为止，水题已经成为过去式了，每一道题都要找答案冥思苦想
2.格式 %I64X ：用于输出【无符号】十六进制数, 用大写字母 | 
转播
