[b]问题说明:[/b]
现在的一些高级程序语言对于字符串的处理支持越来越大,不过字符串搜寻本身仍是值得探讨的课题,在这里以Boyer Moore法来说明如何进行字符串说明,这个方法速度快且容易理解。
import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader;
public class StringMatch { private int[] skip; private int p; private String str; private String key;
public StringMatch(String key) { skip = new int[256]; this.key = key;
for(int k = 0; k <= 255; k++) skip[k] = key.length(); for(int k = 0; k < key.length() - 1; k++) skip[key.charAt(k)] = key.length() - k - 1; }
public void search(String str) { this.str = str; p = search(key.length()-1, str, key); }
private int search(int p, String input, String key) { while(p < input.length()) { String tmp = input.substring( p-key.length()+1, p+1);
if(tmp.equals(key)) // 比较两个字符串是否相同 return p-key.length()+1; p += skip[input.charAt(p)]; }
return -1; }
public boolean hasNext() { return (p != -1); }
public String next() { String tmp = str.substring(p); p = search(p+key.length()+1, str, key); return tmp; }
public static void main(String[] args) throws IOException { BufferedReader bufReader = new BufferedReader( new InputStreamReader(System.in));
System.out.print("请输入字符串:"); String str = bufReader.readLine(); System.out.print("请输入搜寻关键字:"); String key = bufReader.readLine();
StringMatch strMatch = new StringMatch(key); strMatch.search(str);
while(strMatch.hasNext()) { System.out.println(strMatch.next()); } } }
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