依靠JAXBContext轻松实现Java和xml的互相转换

类文件注解：@XmlRootElement不可缺少

@XmlRootElement  
public class Man {  
    private String name;  
    private int age;  
 
    public Student() {  
        super();  
    } 
    public Student(String name, int age) {  
        super();  
        this.name = name;  
        this.age = age;  
    }  
    public String getName() {  
        return name;  
    }  
    public void setName(String name) {  
        this.name = name;  
    }  
    public int getAge() {  
        return age;  
    }  
    public void setAge(int age) {  
        this.age = age;  
    }   
}

Java 转换 Xml：

@Test  
public void testJava2Xml(){  
    try {  
        JAXBContext jc = JAXBContext.newInstance(Man.class);  
        Marshaller ms = jc.createMarshaller();  
        Man man = new Man("man",100);  
        ms.marshal(man, System.out);  
    } catch (JAXBException e) {  
        e.printStackTrace();  
    }  
}

Xml 转换 Java:

@Test  
public void testXml2Java() throws JAXBException{  
    String xml = "<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\"?><Man><age>100</age><name>man</name></Man>";  
    JAXBContext jc = JAXBContext.newInstance(Man.class);  
    Unmarshaller unmar = jc.createUnmarshaller();  
    Man man = (Man) unmar.unmarshal(new StringReader(xml));  
    System.out.println(man.getName());  
}

感谢阅读，如果感觉可以评论点赞！！！！