hdu 2055 An easy problem

Problem Description

we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).

Input

On the first line, contains a number T.then T lines follow, each line is a case.each case contains a letter and a number.

Output

for each case, you should the result of y+f(x) on a line.

Sample Input

6 R 1 P 2 G 3 r 1 p 2 g 3

Sample Output

19 18 10 -17 -14 -4

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#include<stdio.h>
#include<string.h>
   int f(char x)
     {
      if(x>='a'&&x<='z')
         return -(x-'a'+1);
      if(x>='A'&&x<='Z')
         return (x-'A')+1;
     }
  int main()
   {
    int n;
     char x;
      int y;
      int sum;
     scanf("%d",&n);
       
       while(n--)
        { getchar();  //ÎÊÌâÔÚ´Ë
          scanf("%c%d",&x,&y);
            sum=y+f(x);
          printf("%d\n",sum);
            
            
        }
   
      return 0;
   }