|
#include<stdio.h>
int main()
{
int i,j,k;
while(scanf("%d/%d/%d",&i,&j,&k) !=EOF){
if((i%4==0 && i%100!=0)||(i%400==0)){
switch(j){
case 1: printf("%d\n",k); break;
case 2: printf("%d\n",31+k); break;
case 3: printf("%d\n",60+k); break;
case 4: printf("%d\n",91+k); break;
case 5: printf("%d\n",121+k); break;
case 6: printf("%d\n",152+k); break;
case 7: printf("%d\n",182+k); break;
case 8: printf("%d\n",213+k); break;
case 9: printf("%d\n",244+k); break;
case 10: printf("%d\n",274+k); break;
case 11: printf("%d\n",305+k); break;
case 12: printf("%d\n",335+k); break;
}
}
else{
switch(j){
case 1: printf("%d\n",k); break;
case 2: printf("%d\n",31+k); break;
case 3: printf("%d\n",60+k-1); break;
case 4: printf("%d\n",91+k-1); break;
case 5: printf("%d\n",121+k-1); break;
case 6: printf("%d\n",152+k-1); break;
case 7: printf("%d\n",182+k-1); break;
case 8: printf("%d\n",213+k-1); break;
case 9: printf("%d\n",244+k-1); break;
case 10: printf("%d\n",274+k-1); break;
case 11: printf("%d\n",305+k-1); break;
case 12: printf("%d\n",335+k-1); break;
}
}
}
return 0;
}
/*
第几天？
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 73162 Accepted Submission(s): 27675
Problem Description
给定一个日期，输出这个日期是该年的第几天。
Input
输入数据有多组，每组占一行，数据格式为YYYY/MM/DD组成，具体参见sample input ,另外，可以向你确保所有的输入数据是合法的。
Output
对于每组输入数据，输出一行，表示该日期是该年的第几天。
Sample Input
1985/1/20
2006/3/12
Sample Output
20
71
*/ | 
转播
