|
Problem Description
we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).
Input
On the first line, contains a number T.then T lines follow, each line is a case.each case contains a letter and a number.
Output
for each case, you should the result of y+f(x) on a line.
Sample Input
6
R 1
P 2
G 3
r 1
p 2
g 3
Sample Output
19
18
10
-17
-14
-4
题意很好理解，问题也很简单，不过我的代码一直有bug，当时很生气啊，，最后冷静下来才发现就是因为在输入样例数t之后忘记用一个getchar（）来存取换行了。再之后就A了。大家做题的时候要细心啊
#include<stdio.h>
int main()
{
int i,m,n,t;
char s;
scanf("%d",&t);
getchar();
while(t --)
{
scanf("%c %d",&s,&n);
getchar();
if(s >= 'a' && s <= 'z')
m = -(s - 'a') - 1;
else
m = s - 'A' + 1;
printf("%d\n",m+n);
}
return 0;
}
| 
转播
