oracle当前月添加一列显示前几个月的累计值

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匿名技术用户   2020-12-28 03:32   28   0

create table test_leiji(rpt_month_id number(8),
current_month NUMBER(12,2));

insert into test_leiji (RPT_MONTH_ID, CURRENT_MONTH) values (200901, 380128.344363);
insert into test_leiji (RPT_MONTH_ID, CURRENT_MONTH) values (200902, 274474.595772);
insert into test_leiji (RPT_MONTH_ID, CURRENT_MONTH) values (200903, 309427.898521);
insert into test_leiji (RPT_MONTH_ID, CURRENT_MONTH) values (200904, 379854.833875);

insert into test_leiji (RPT_MONTH_ID, CURRENT_MONTH) values (201001, 380128.344363);
insert into test_leiji (RPT_MONTH_ID, CURRENT_MONTH) values (201002, 274474.595772);
insert into test_leiji (RPT_MONTH_ID, CURRENT_MONTH) values (201003, 309427.898521);
insert into test_leiji (RPT_MONTH_ID, CURRENT_MONTH) values (201004, 379854.833875);


select * from test_leiji t


SELECT rpt_month_id,
current_month,
SUM (current_month) OVER (PARTITION BY SUBSTR (rpt_month_id, 1, 4)order by rpt_month_id) sum_month
FROM test_leiji
order by rpt_month_id;

显示结果如图:


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